TI-83 Plus Calculations for Sample Final Examination

 

1.         STAT  TESTS  6:2-PropZTest…

  z=.980479796

  P=.1634246669

  ^p1=.0065958768

  ^p2=.0045425049

  ^p=.0065063649

  n1=33809

  n2=1541

 
 

  x1:  223

  n1:  33809

  x2:  7

  n2:  1541

  p1:                 >p2

  Calculate

 
 
                       

 

 

 

 

 

 

 

 

2. (a)    Enter data into list L1 and list L2.  Highlight L3.  L3 = L2 – L1.

            STAT  TESTS  2:Ttest…

  m>0

  t=2.587576203

  P=.0304195866

  x-=157

  Sx=135.6723996

  n=5

 
 

  Inpt:  Data

  m0:  0

  List:  L3

  Freq:  1

  m:                   >m0

  Calculate       

 
           

 

 

 

 

 

 

 

 

    (b)    STAT  TESTS  8:Tinterval…

  (-70.34, 384.34)

  x-=157

  Sx=135.6723996

  n=5
 

  Inpt:  Data

  List:  L3

  Freq:  1

  C-Level:  .98

  Calculate
 
           

 

 

 

 

 

 

 

3.         STAT  TESTS  B:2-PropZInt…  (Reverse populations 1 & 2 to get improvement.)

  (.07811, .26725)

  ^p1=.321192053

  ^p2=.1485148515

  n1=302

  n2=202
 

  x1:  96+1

  n1:  300+2

  X2:  29+1

  N2:  200+2

  C-Level:  .99

  Calculate
 
           

 

 

 

 

 

 

 

4. (b)    2nd  DISTR  5:tcdf(3.187693,100,16)   = .0028619096  (one-tailed probability)

            ´ 2  ENTER     yields P = .0057238192 » .0057.

    (c)    ^my  =  ^y  =  30.84249 + 1.186813´16  =  49.831498  » 49.831 dollars.

The TI-83 Plus could do LinRegTTest on data entered into lists, but it doesn’t given the required confidence interval.  See answer book key for that.