A straight-line program to do date format conversion

In this brief lab you will write a straight-line program to perform date format conversion. Straight-line programs have no flow-control: no conditional statements, loops or recursive function calls. (In fact, you won't see flow control until Chapter 4.) Although people seldom write straight-line programs, they can make for instructive and challenging puzzles.

Date conversion (2 points)

  1. Write and compile a straight-line program to perform date format conversions. I'll explain by example. The user will type input in the form 10/05/98 and the computer should output, say, Oct 05, 1998. (See Exercise P2.22 on page 86 for a hint. Another hint: It's easiest if your program first reads in the month, 10, as an integer, then reads in the rest of the line /05/98, as a string. You should only use stuff you have read about in Chapters 1 and 2 in the book.)

    Be sure that all variable names are carefully chosen, and that the program is indented properly. You can mark the whole file as the region using C-x h and then indent the file using C-M-\ or M-x indent-region.

    Be sure your program compiles and runs. Perform several tests of the program before getting checked off.

  2. Check-off: Leave the window with your tests open on your screen, as well as the Emacs file containing your program.

Improving the program (OPTIONAL)

You are encouraged to work with a neighbor on this part. If you do work with someone else, you'll be checked off together; you needn't each have your own copy of a working program.

To do this assignment, you'll need a way to convert digits to integers: If str is a string, the expression (str[4] - '0') returns an integer whose value is the digit in position 4 of the string. (Recall that the first position is 0, so this converts the 5th character in str to an integer.)

For example, the following program prints the number 400 followed by a newline.

  #include <iostream>
  #include "ccc_ansi.h"
/*#include <string> */     /* Not Needed */
  using namespace std;
  main() {
     string str = "Pi=3.14159";
     cout << 100*(str[6] - '0') << endl;
I should make a couple additional notes on how to compile this program: Improve your program by making the following improvements. Be sure to save your last properly working copy in a backup file before you take on each new challenge. This way, if you get stuck, at least you can go back to something that works.
  1. Improve the format so that a leading zero in front of the date is removed. I.e.,

  2. Make it so any year below 50 is interpreted as occuring after the year 2000. So, Hint: Use integer arithmetic operations, i.e., % / * + and/or -.

  3. Check-off: Leave the window with your tests open on your screen, as well as the Emacs file containing your improved program.

  4. (optional challenge) Make it so that the months are written unabbreviated: December 18, 2023. The challenge here is that there should not be additional leading or trailing spaces, so months use up a variable number of characters depending on how long it is written out in English.