Physlet Illustration: Keplerian Telescope |
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In this simulation, a Keplerian telescope is constructed from two converging
lenses. The objective has a focal length of 9.0 mm. The user may drag the
source and the eyepiece as well as change its focal length (1 to 7 mm).
What determines the angular magnification of such a telescope?
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Hints:
- Drag the eyepiece until the image is in focus. (Hint: The object
is at infinity so the rays arrive parallel to each other. The rays that
form the final, virtual image must also be parallel.)
- Change the focal length of the eyepiece. Does the focus
change? What else changes?
- What can one say about the distance between the lenses in this type of
telescope?
- Angular magnification may be calculated from the ratio of the the
outgoing and incoming angles of the rays.
- Another way to calculate the magnification involves the ratio of the focal
lengths of the two lenses.
Does this calculated value agree with the measured value?
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Reference
See The New Cosmic Universe, Sections 31.7
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Illustration written by Chuck
Niederriter and Steve Mellema
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